jquery访问servlet并返回数据到页面的方法

本文实例讲述了jquery访问servlet并返回数据到页面的方法。分享给大家供大家参考。具体实现方法如下：

1. servlet:AjaxServlet.java如下：

package com.panlong.servlet;

import java.io.IOException;
import java.io.PrintWriter;
import java.net.URLDecoder;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class AjaxServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;
    protected void doGet(HttpServletRequest req, HttpServletResponse resp)
            throws ServletException, IOException {
        Integer total = (Integer) req.getSession().getAttribute("total");
        int temp = 0;
        if(total == null ){
            temp = 1;
        }else{
            temp = total.intValue() + 1;
        }
    req.getSession().setAttribute("total",temp);
        try {
            //1.取参数
            resp.setContentType("text/html;charset=GBK");
            PrintWriter out = resp.getWriter();
            String old = req.getParameter("name");
            //2.检查参数是否有问题
            //String name = new String(old.getBytes("iso8859-1"),"UTF-8");
            String name = URLDecoder.decode(old,"UTF-8");
            if("".equals(old) || old == null){
                out.println("用户名必须输入");
            }else{
                if("liling".equals(name)){
                    out.println("恭喜登录成功");
                    return;
                }else{
                    out.println("该用户名未注册，您可以注册["+name+"]这个用户名"+temp);
                }
            }
        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        //3.检验操作
    }
    protected void doPost(HttpServletRequest req, HttpServletResponse resp)
            throws ServletException, IOException {
        doGet(req, resp);
    }
}

2. verify.js如下：

复制代码代码如下:

function verify(){  

    //解决中文乱码问题的方法1,页面端发出的数据作一次encodeURI，服务端使用new String(old.getBytes("iso8859-1"),"UTF-8");  

    //解决中文乱码问题的方法2,页面端发出的数据作两次encodeURI,服务端使用String name = URLDecoder.decode(old,"UTF-8");  

    var url = "servlet/AjaxServlet?name="+encodeURI(encodeURI($("#userName").val()));  

    url = convertURL(url);  

    $.get(url,null,function(data){  

        $("#result").html(data);  

    });  

}  

//给url地址增加时间蒫，难过浏览器，不读取缓存  

function convertURL(url){  

    //获取时间戳  

    var timstamp = (new Date()).valueOf();  

    //将时间戳信息拼接到url上  

    if(url.indexOf("?") >=0){  

        url = url + "&t=" + timstamp;  

    }else{  

        url = url + "?t=" + timstamp;  

    }  

    return url;  

}

3. 前台页面如下：

复制代码代码如下:

<!DOCTYPE html>  

<html>  

  <head>  

    <title>AJAX实例</title>  

    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">  

    <meta http-equiv="description" content="this is my page">  

    <meta http-equiv="content-type" content="text/html; charset=GBK">  

    <script type="text/javascript" src="js/verify.js"></script>  

    <script type="text/javascript" src="js/jquery.js"></script>  

    <!--<link rel="stylesheet" type="text/css" href="./styles.css">-->  

  </head>  

  <body>  

        <font color="blue" size="2">请输入用户名：</font>   

         <input type="text" id="userName" /><font color="red" size="2"><span id="result" >*</span></font><br/><br/>  

         <!-- <div id="result"></div> -->  

          <input type="submit" name="提交" value="提交"  onclick="verify()"/>  

  </body>

</html>

希望本文所述对大家的Ajax程序设计有所帮助。