[LintCode/LeetCode] Implement Trie

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Problem

Implement a trie with insert, search, and startsWith methods.

Notice

You may assume that all inputs are consist of lowercase letters a-z.

Example

insert("lintcode")
search("code") // return false
startsWith("lint") // return true
startsWith("linterror") // return false
insert("linterror")
search("lintcode) // return true
startsWith("linterror") // return true

Note

首先,我们应该了解字典树的性质和结构,就会很容易实现要求的三个相似的功能:插入,查找,前缀查找。
既然叫做字典树,它一定具有顺序存放26个字母的性质。另外,为了实现和区别全词查找和前缀查找,应该有一个标记。所以,在字典树的class里面,添加chexistchildren三个参数。

插入操作:建立结点pre,复制root。在prechildren[index]存放插入词汇word的第i个字符(用数字0到25表示a~z的26个字母,记作index),依次类推。若当前的children不存在,则建立大小为26的children结点数组。若children结点数组里的第index个TrieNode为空,则放入新的值为word.charAt(i)的TrieNode。然后pre前进到当前结点的children,pre.children[index],继续循环操作word的下一个字符。直到放入word的最后一个字符以后,修改pre.exist值为true,说明pre之前的分支完整放入了word。

查找操作:同插入一样,复制root到结点pre,然后遍历查找word的每一个字符word.charAt(i),若循环里某个pre.children[index]不存在,或者word的最后一个字符的exist标记为false,则返回false。否则,循环结束,返回true

前缀查找操作:唯一和查找操作不同的地方,是不要求word的最后一个字符的exist标记为true。只要遍历完String prefix,就返回true

Solution

class TrieNode {
    // Initialize your data structure here.
    boolean exist;
    char ch;
    TrieNode[] children;
    public TrieNode() {
        
    }
    public TrieNode(char ch) {
        this.ch = ch;
    }
}

public class Trie {
    private TrieNode root;

    public Trie() {
        root = new TrieNode();
    }

    // Inserts a word into the trie.
    public void insert(String word) {
        if (word == null || word.length() == 0) return;
        TrieNode pre = root;
        for (int i = 0; i < word.length(); i++) {
            if (pre.children == null) pre.children = new TrieNode[26];
            int index = word.charAt(i) - 'a';
            if (pre.children[index] == null) {
                pre.children[index] = new TrieNode(word.charAt(i));
            }
            pre = pre.children[index];
            if (i == word.length()-1) pre.exist = true;
        }
    }

    // Returns if the word is in the trie.
    public boolean search(String word) {
        if (word == null || word.length() == 0) return false;
        TrieNode pre = root;
        for (int i = 0; i < word.length(); i++) {
            int index = word.charAt(i) - 'a';
            if (pre.children == null || pre.children[index] == null) return false;
            if (i == word.length()-1 && pre.children[index].exist == false) return false;
            pre = pre.children[index];
        }
        return true;
    }

    // Returns if there is any word in the trie
    // that starts with the given prefix.
    public boolean startsWith(String prefix) {
        if (prefix == null || prefix.length() == 0) return false;
        TrieNode pre = root;
        for (int i = 0; i < prefix.length(); i++) {
            int index = prefix.charAt(i) - 'a';
            if (pre.children == null || pre.children[index] == null) return false;
            pre = pre.children[index];
        }
        return true;
    }
}